document.write( "Question 713081: I would be grateful if you could kindly help me to get a step by step solution to following quadratic equation\r
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document.write( "Solve: (2x+1)(2x+3)(x-1)(x-2) = 150\r
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document.write( "Thanks & Regards,
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document.write( "Vijayan C
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Algebra.Com's Answer #438289 by Edwin McCravy(20056)![]() ![]() You can put this solution on YOUR website! \r\n" ); document.write( "\r\n" ); document.write( "(2x+1)(2x+3)(x-1)(x-2) = 150 \r\n" ); document.write( "\r\n" ); document.write( "FOIL out the first two parentheses on the left\r\n" ); document.write( "\r\n" ); document.write( "(4x²+8x+3)(x-1)(x-2) = 150\r\n" ); document.write( "\r\n" ); document.write( "FOIL out the last two parentheses on the left\r\n" ); document.write( "\r\n" ); document.write( "(4x²+8x+3)(x²-3x+2) = 150\r\n" ); document.write( "\r\n" ); document.write( "You have to use a generalized version of FOIL\", which is:\r\n" ); document.write( "\r\n" ); document.write( "(F+M+L)(F+M+L) = FF+FM+FL+MF+MM+ML+LF+LM+LL \r\n" ); document.write( "\r\n" ); document.write( "Where F means the first term, M means the middle term, \r\n" ); document.write( "and L means the last term:\r\n" ); document.write( "\r\n" ); document.write( "(4x²)(x²)+(4x²)(-3x)+(4x²)(2)+(8x)(x²)+(8x)(-3x)+(8x)(2)+(3)(x²)+(3)(-3x)+(3)(2)\r\n" ); document.write( "\r\n" ); document.write( "4x4-12x³+8x²+8x³-24x²+16x+3x²-9x+6 = 150\r\n" ); document.write( "\r\n" ); document.write( "4x4-4x³-13x²+7x-144 = 0\r\n" ); document.write( "\r\n" ); document.write( "You can factor x² out of the first two terms:\r\n" ); document.write( "\r\n" ); document.write( "x²[4x²-4x]-13x²+7x-144 = 0\r\n" ); document.write( "\r\n" ); document.write( "Complete the square in the bracket by adding 1 and subtracting\r\n" ); document.write( "1 inside the bracket:\r\n" ); document.write( "\r\n" ); document.write( "x²[4x²-4x+1-1]-13x²+7x-144 = 0\r\n" ); document.write( "\r\n" ); document.write( "Factor the first three terms inside the bracket as a perfect\r\n" ); document.write( "square:\r\n" ); document.write( "\r\n" ); document.write( "x²[(2x-1)²-1]-13x²+7x-144 = 0\r\n" ); document.write( "\r\n" ); document.write( "Distribute the x² to remove the bracket:\r\n" ); document.write( "\r\n" ); document.write( "x²(2x-1)²-x²-13x²+7x-144 = 0\r\n" ); document.write( "\r\n" ); document.write( "Combine the x² terms\r\n" ); document.write( "\r\n" ); document.write( "x²(2x-1)²-14x²+7x-144 = 0\r\n" ); document.write( "Factor -7x out of the -14x²+7x\r\n" ); document.write( "\r\n" ); document.write( "x²(2x-1)²-7x(2x-1)-144 = 0\r\n" ); document.write( "\r\n" ); document.write( "The first term can be written [x(2x-1)]²\r\n" ); document.write( "\r\n" ); document.write( "[x(2x-1)]²-7x(2x-1)-144 = 0\r\n" ); document.write( "\r\n" ); document.write( "Let u = x(2x-1)\r\n" ); document.write( " u² = [x(2x-1)]²\r\n" ); document.write( "\r\n" ); document.write( "u² - 7u - 144 = 0\r\n" ); document.write( "\r\n" ); document.write( "(u - 16)(u + 9) = 0\r\n" ); document.write( "\r\n" ); document.write( "u - 16 = 0; u + 9 = 0\r\n" ); document.write( " u = 16; u = -9\r\n" ); document.write( "\r\n" ); document.write( "Since u = x(2x-1)\r\n" ); document.write( "\r\n" ); document.write( " x(2x-1) = 16; x(2x-1) = 9\r\n" ); document.write( " 2x² - x = 16; 2x² - x = 9\r\n" ); document.write( " 2x²-x-16 = 0; 2x²-x-9 = 0\r\n" ); document.write( " x =\n" ); document.write( " |