document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=712851>Question 712851</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Contract the expressions. That is, use the properties of logarithms to write each expression as a single logarithm with a coefficient of 1. \r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "ln 3 &#8722; 2 ln(8 + 7) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #438247 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=438247\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> ln 3 &#8722; 2 ln(8 + 7)<BR>\n" );
document.write( "----<BR>\n" );
document.write( "ln(3) - 2*ln(15)<BR>\n" );
document.write( "----<BR>\n" );
document.write( "ln(3) - ln(15^2)<BR>\n" );
document.write( "---<BR>\n" );
document.write( "ln(3) - ln(225)<BR>\n" );
document.write( "---<BR>\n" );
document.write( "= ln(3/225)<BR>\n" );
document.write( "====================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );