document.write( "Question 712924: elaine added 3 lbs. of peanuts to a 15 lb. mixture containing peanuts and raisins. if the original mixture was 25% peanuts, what is the percent if peanuts in the new mixture? \n" ); document.write( "
Algebra.Com's Answer #438217 by josgarithmetic(39618)\"\" \"About 
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p for pounds peanuts to add to original mixture, 3 pounds
\n" ); document.write( "v for pounds original mixture, 15 pounds\r
\n" ); document.write( "\n" ); document.write( "H for percent peanuts percent, 100%
\n" ); document.write( "L for percent peanuts in the mix before adding the 3 pounds of it, 25%
\n" ); document.write( "T UNKNOWN % peanuts in the mix after adding the 3 pounds of it
\n" ); document.write( "M = 3+15=18 pounds of final mixture\r
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\n" ); document.write( "\n" ); document.write( "Formula for T is straight-forward.
\n" ); document.write( "\"highlight%28T=%28H%2Ap%2BL%2Av%29%2F%28M%29%29\"
\n" ); document.write( "We know everything to calculate and find T. \r
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\n" ); document.write( "\n" ); document.write( "Percent Peanuts = \"%28100%2A3%2B25%2A15%29%2F18\" %
\n" ); document.write( "=\"37.5\"% peanuts
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