document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=712913>Question 712913</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Trying to graph the parabola y=-3(x+7)^2-8 and get vertex of (-7, -8) with another point of (0, -155) which seems odd.  Is this correct?  In order to graph, should I try x=something other than \"0\"??<BR>\n" );
document.write( "Thanks </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #438209 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley79><B>checkley79(3341)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley79><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=438209\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> y=-3(x+7)^2-8<BR>\n" );
document.write( "y=-3(x^2+14x+49)-8<BR>\n" );
document.write( "y=--3x^2-42x-147-8<BR>\n" );
document.write( "y=-3x^2-42x-155<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+graph%28+300%2C+200%2C+-26%2C+5%2C+-160%2C+10%2C+-3x%5E2+-42x-155%29+ ALIGN=MIDDLE  ALT=\"+graph%28+300%2C+200%2C+-26%2C+5%2C+-160%2C+10%2C+-3x%5E2+-42x-155%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" >  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );