document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=712844>Question 712844</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A ball is thrown into the air vertically with a velocity of 112 feet per second. The ball was released 6 feet above the ground. The height above the ground t seconds after release is modeled by h(t)=-16t^2+112t+6. 1.)When will the ball reach 130 feet? 2.)Will the ball reach 250 feet? 3.)In how many seconds after its release will the ball hit the ground? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #438187 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=438187\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> h(t)=-16t^2+112t+6. 1.)When will the ball reach 130 feet?<BR>\n" );
document.write( "h(t) = -16t^2 + 112t + 6<BR>\n" );
document.write( "-16t^2 + 112t + 6 = 130<BR>\n" );
document.write( "Solve for t<BR>\n" );
document.write( "(There will be 2 solutions, 130 ft going up, 130 ft coming back down)<BR>\n" );
document.write( "---------------<BR>\n" );
document.write( " 2.)Will the ball reach 250 feet? <BR>\n" );
document.write( "-16t^2 + 112t + 6 = 250<BR>\n" );
document.write( "Same as #1<BR>\n" );
document.write( "---------------------<BR>\n" );
document.write( "3.)In how many seconds after its release will the ball hit the ground?<BR>\n" );
document.write( "-16t^2 + 112t + 6 = 0<BR>\n" );
document.write( "Ignore the negative solution<BR>\n" );
document.write( " </SPAN>\n" );
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