document.write( "Question 712835: first clear of fractions then solve using substitution\r
\n" ); document.write( "\n" ); document.write( "x/2 - y/3= 5/6\r
\n" ); document.write( "\n" ); document.write( "x/5 - y/4= 29/10
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Algebra.Com's Answer #438180 by Alan3354(69443)\"\" \"About 
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first clear of fractions then solve using substitution\r
\n" ); document.write( "\n" ); document.write( "x/2 - y/3= 5/6\r
\n" ); document.write( "\n" ); document.write( "x/5 - y/4= 29/10
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\n" ); document.write( "I wouldn't do it that way, but...
\n" ); document.write( "Multiply the 1st eqn by 6 & and the 2nd by 20
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\n" ); document.write( "3x - 2y = 5
\n" ); document.write( "4x - 5y = 58
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\n" ); document.write( "Multiply the 1st eqn by 4 and the 2nd by 3
\n" ); document.write( "12x - 8y = 20 --> 12x = 8y+20
\n" ); document.write( "12x -15y = 174
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\n" ); document.write( "Sub for 12x in the 2nd eqn
\n" ); document.write( "(8y+20) - 15y = 174
\n" ); document.write( "-7y = 154
\n" ); document.write( "y = -22
\n" ); document.write( "etc
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