document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=712784>Question 712784</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how do i solve 1-csc^2theta= -3 for 0 degrees is less than or equal to 0 which is less than 360 degrees? I have tried switching 1-csc^2theta to cot^2theta. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #438149 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=438149\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> how do i solve 1-csc^2theta= -3 for 0 degrees is less than or equal to 0 which is less than 360 degrees? I have tried switching 1-csc^2theta to cot^2theta.<BR>\n" );
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document.write( "Correct:<BR>\n" );
document.write( "cot^2 = -3<BR>\n" );
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document.write( "cot(x) = sqrt(3)<BR>\n" );
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document.write( "you might recognize this as x = 30 degrees or pi/6 in QI<BR>\n" );
document.write( "OR x = (7/6)pi or 210 degrees in QIII.<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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