document.write( "Question 712773: a cruise boat travels 96 miles down stream in 3hours and return upstream in 6 hours. find the rate of the stream. \n" ); document.write( "

Algebra.Com's Answer #438142 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
Let $\"+s+\"$ = the rate of the stream in mi/hr
\n" ); document.write( "Let $\"+b+\"$ = the rate of the boat with no current in mi/hr
\n" ); document.write( "-----------
\n" ); document.write( "Going upstream, speed =
\n" ); document.write( " $\"+b+-+s+\"$ mi/hr
\n" ); document.write( "Going downstream, speed =
\n" ); document.write( " $\"+b+%2B+s+\"$ mi/hr
\n" ); document.write( "----------
\n" ); document.write( "given:
\n" ); document.write( " $\"+b+%2B+s+=+96%2F3+\"$
\n" ); document.write( " $\"+b+%2B+s+=+32+\"$ mi/hr
\n" ); document.write( "and
\n" ); document.write( " $\"+b+-+s+=+96%2F6+\"$
\n" ); document.write( " $\"+b+-+s+=+16+\"$ mi/hr
\n" ); document.write( "-------------------
\n" ); document.write( "Add the equations
\n" ); document.write( " $\"+b+%2B+s+=+32+\"$
\n" ); document.write( " $\"+b+-+s+=+16+\"$
\n" ); document.write( " $\"+2b+=+48+\"$
\n" ); document.write( " $\"+b+=+24+\"$
\n" ); document.write( "and, since
\n" ); document.write( " $\"+b+%2B+s+=+32+\"$
\n" ); document.write( " $\"+24+%2B+s+=+32+\"$
\n" ); document.write( " $\"+s+=+8+\"$
\n" ); document.write( "The speed of the stream is 8 mi/hr
\n" ); document.write( " \n" ); document.write( "

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