document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=62980>Question 62980</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0132191415/algebrahomeworkh>college algebra</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> Condense....<BR>\n" );
document.write( "log3 (5x + 3) = 2 + log3 (x-1) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #43814 by </B><A HREF=/tutors/aboutme.mpl?userid=uma><B>uma(370)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=uma><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=43814\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> log 3 (5x+3) = 2 + log 3 (x-1)\r<BR>\n" );
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document.write( "adding - log 3 (x-1) to both the sides we get,\r<BR>\n" );
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document.write( "log 3 (5x+3) - log 3 (x-1) = 2\r<BR>\n" );
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document.write( "==> log 3 [(5x+3)/(x-1)] = 2  [as loga - logb = log(a/b)]\r<BR>\n" );
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document.write( "==> 5x+3/(x-1) = 3^2 [writing in the exponential form]\r<BR>\n" );
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document.write( "==> (5x+3)/(x-1) = 9\r<BR>\n" );
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document.write( "==> 5x + 3 = 9(x-1)\r<BR>\n" );
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document.write( "==> 5x + 3 = 9x - 9\r<BR>\n" );
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document.write( "==> 5x + 3 - 9x = 9x - 9x - 9\r<BR>\n" );
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document.write( "==> - 4x + 3 = -9\r<BR>\n" );
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document.write( "==> - 4x + 3 - 3 = -9 - 3\r<BR>\n" );
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document.write( "==> - 4x = -12<BR>\n" );
document.write( "==> -4x/-4 = - 12/-4\r<BR>\n" );
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document.write( "==> x = 3\r<BR>\n" );
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document.write( "Thus x = 3\r<BR>\n" );
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document.write( "Good Luck!!! </SPAN>\n" );
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