document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=62979>Question 62979</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0495188751/algebrahomeworkh>Intermediate Algebra</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> Perform the multiplications. Assume that all variables are positive.<BR>\n" );
document.write( "x^4/3(x^2/3+3x^5/3-4x^8/3) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #43813 by </B><A HREF=/tutors/aboutme.mpl?userid=uma><B>uma(370)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=uma><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=43813\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x^(4/3)[x^(2/3) + 3x^(5/3) - 4x^(8/3)]\r<BR>\n" );
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document.write( "While multiplying we add the powers of the same bases.\r<BR>\n" );
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document.write( "= x^(4/3 + 2/3) + 3x^(4/3 + 5/3) - 4x^(4/3 + 8/3)\r<BR>\n" );
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document.write( "= x^(6/3) + 3x^(9/3) - 4x^(12/3)\r<BR>\n" );
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document.write( "= x^2 + 3x^3 - 4x^4\r<BR>\n" );
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document.write( "Good Luck!!! </SPAN>\n" );
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