document.write( "Question 62976: FIND THE POLYNOMIAL f(x) OF DEGREE THREE THAT HAS ZEROES AT 1,2, AND 4 SUCH THAT f(0)=-16. \n" ); document.write( "
Algebra.Com's Answer #43811 by Nate(3500)![]() ![]() ![]() You can put this solution on YOUR website! (x - 1)(x - 2)(x - 4) \n" ); document.write( "(x^2 - 3x + 2)(x - 4) \n" ); document.write( "x^3 - 3x^2 + 2x - 4x^2 + 12x - 8 \n" ); document.write( "x^3 -7x^2 + 14x - 8 = f(x) \n" ); document.write( " \n" ); document.write( "All values for x is zero ... so f(0) = - 8 \n" ); document.write( "2*f(0) = -16 \n" ); document.write( "2x^3 - 14x^2 + 28x - 16 = f(x) \n" ); document.write( " |