document.write( "Question 62976: FIND THE POLYNOMIAL f(x) OF DEGREE THREE THAT HAS ZEROES AT 1,2, AND 4 SUCH THAT f(0)=-16. \n" ); document.write( "
Algebra.Com's Answer #43811 by Nate(3500)\"\" \"About 
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(x - 1)(x - 2)(x - 4)
\n" ); document.write( "(x^2 - 3x + 2)(x - 4)
\n" ); document.write( "x^3 - 3x^2 + 2x - 4x^2 + 12x - 8
\n" ); document.write( "x^3 -7x^2 + 14x - 8 = f(x)
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\n" ); document.write( "All values for x is zero ... so f(0) = - 8
\n" ); document.write( "2*f(0) = -16
\n" ); document.write( "2x^3 - 14x^2 + 28x - 16 = f(x)
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