document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=712667>Question 712667</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A hot-air balloon travels round the Earth 1km above the surface, following the equator. How much further does it travel than the distance around the equator? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #438109 by </B><A HREF=/tutors/aboutme.mpl?userid=Simnepi><B>Simnepi(216)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Simnepi><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Simnepi><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=438109\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> because circumference = 2 * pi * radius<BR>\n" );
document.write( "and the difference in the diameter of the earth and the path travelled by the balloon is 1km<BR>\n" );
document.write( "so the balloon travels an extra 2 * pi * 1km<BR>\n" );
document.write( "using a calculator this is 6.28318530718km<BR>\n" );
document.write( "rounding this to the nearest metre gives<BR>\n" );
document.write( "6.283km </SPAN>\n" );
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