document.write( "Question 712639: If 123 base b =83 solve for b. \r
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Algebra.Com's Answer #438095 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
In general, to convert from base b to base 10, you plug the digits a0...an from left to right into the polynomial of the form a0*b^n + ... an*b^0\r
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\n" ); document.write( "\n" ); document.write( "So that would mean\r
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\n" ); document.write( "\n" ); document.write( "xyz base b = x*b^2 + y*b^1 + z*b^0\r
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\n" ); document.write( "\n" ); document.write( "123 base b = 1*b^2 + 2*b^1 + 3*b^0\r
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\n" ); document.write( "\n" ); document.write( "123 base b = 1*b^2 + 2*b^1 + 3*b^0\r
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\n" ); document.write( "\n" ); document.write( "123 base b = 1*b^2 + 2*b + 3*b^0\r
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\n" ); document.write( "\n" ); document.write( "83 = 1*b^2 + 2*b + 3*b^0\r
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\n" ); document.write( "\n" ); document.write( "1*b^2 + 2*b + 3*b^0 = 83\r
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\n" ); document.write( "\n" ); document.write( "b^2 + 2b + 3 = 83\r
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\n" ); document.write( "\n" ); document.write( "b^2 + 2b + 3 - 83 = 0\r
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\n" ); document.write( "\n" ); document.write( "b^2 + 2b - 80 = 0\r
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\n" ); document.write( "\n" ); document.write( "(b+10)(b-8) = 0\r
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\n" ); document.write( "\n" ); document.write( "b+10 = 0 or b-8 = 0\r
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\n" ); document.write( "\n" ); document.write( "b = -10 or b = 8\r
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\n" ); document.write( "\n" ); document.write( "Toss out the negative base\r
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\n" ); document.write( "\n" ); document.write( "The only solution left is b = 8\r
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\n" ); document.write( "\n" ); document.write( "So 123 base 8 = 83 base 10\r
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