document.write( "Question 62973: THE PEROD OF A SIMPLE PENDULUM IS DIRECTLY PROPORTIONAL TO THE SQUARE ROOT OF ITS LENGTH. IF A PENDULUM HAS A LENGTH OF 6 FEET AND A PERIOD OF 2 SECONDS, TO WHAT LENGTH SHOULD IT BE SHORTENED TO ACHIEVE A 1 SECOND PERIOD? \n" ); document.write( "
Algebra.Com's Answer #43807 by uma(370)\"\" \"About 
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If p denotes the period, l the length and K the constant of proportionality then,\r
\n" ); document.write( "\n" ); document.write( "p = K*l^2\r
\n" ); document.write( "\n" ); document.write( "When l = 6 ft and p = 2 seconds then,\r
\n" ); document.write( "\n" ); document.write( "2 = K*(6^2)\r
\n" ); document.write( "\n" ); document.write( "==> 2 = K* 36
\n" ); document.write( "==> 2/36 = K*36/36
\n" ); document.write( "==> 1/18 = K\r
\n" ); document.write( "\n" ); document.write( "Thus the equation becomes p = (1/18)*l^2
\n" ); document.write( "when p = 1,\r
\n" ); document.write( "\n" ); document.write( "1 = (1/18) l^2
\n" ); document.write( "multiplying both the sides by 18,
\n" ); document.write( "1*18 = l^2
\n" ); document.write( "==> 18 = l^2
\n" ); document.write( "taking square root on both the sides,\r
\n" ); document.write( "\n" ); document.write( "sqrt(18) = l
\n" ); document.write( "==> 4.2 = l\r
\n" ); document.write( "\n" ); document.write( "Thus to achieve a period of 1 second, the length should be (approx) 4.2 ft.\r
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\n" ); document.write( "\n" ); document.write( "Good Luck1!!
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