document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=712592>Question 712592</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A triangle contains three angles: a,b, and c. Angle b is twice angle a, and c is 20 more than angle a. Find the measures of the . The measures of the the angles inside a triangle total 180 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #438069 by </B><A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><B>algebrahouse.com(1659)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=algebrahouse.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=438069\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x = angle a<BR>\n" );
document.write( "2x = angle b {angle b is twice angle a}<BR>\n" );
document.write( "x + 20 = angle c {angle c is 20 more than angle a}\r<BR>\n" );
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document.write( "x + 2x + x + 20 = 180 {angles of a triangle add up to 180}<BR>\n" );
document.write( "4x + 20 = 180 {combined like terms}<BR>\n" );
document.write( "4x = 160 {subtracted 20 from each side}<BR>\n" );
document.write( "x = 40 {divided each side by 4}<BR>\n" );
document.write( "2x = 80 {substituted 40, in for x, into 2x}<BR>\n" );
document.write( "x + 20 = 60 {substituted 40, in for x, into x + 20}\r<BR>\n" );
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document.write( "40°, 60°, and 80° are the three angles<BR>\n" );
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