document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=712598>Question 712598</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the first number is 5 less than 3 times the second number. Twice the first number plus the second number is 137.  find the two numbers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #438065 by </B><A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><B>algebrahouse.com(1659)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=algebrahouse.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=438065\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x = second number<BR>\n" );
document.write( "3x - 5 = first number  {first number is 5 less than three times the second}\r<BR>\n" );
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document.write( "2(3x - 5) + x = 137 {twice the first plus the second is 137}<BR>\n" );
document.write( "6x - 10 + x = 137 {used distributive property}<BR>\n" );
document.write( "7x - 10 = 137 {combined like terms}<BR>\n" );
document.write( "7x = 147 {added 10 to each side}<BR>\n" );
document.write( "x = 21 {divided each side by 7}<BR>\n" );
document.write( "3x - 5 = 58 {substituted 21, in for x, into 3x - 5}\r<BR>\n" );
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document.write( "58 is the first number and 21 is the second<BR>\n" );
document.write( "<br>For more help from me, visit: <a  rel=nofollow HREF= \"http://www.algebrahouse.com/\" target = \"_blank\">www.algebrahouse.com</a><br><br>\r<BR>\n" );
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