document.write( "Question 62972: a wire of length 20 m and diameter 0.6 cmTHE ELECTRICAL RESISTANCE r OF A WIRE VARIES DIRECTLY AS ITS LENGTH l AND INVERSELY AS THE SQUARE OF ITS DIAMETER. A WIRE 20 METERS LONG AND 0.6 CENTIMETERS IN DIAMETER MADE FROM A CERTAIN ALLOY HAS A RESISTANCE OF 36 OHMS. WHAT IS THE RESISTANCE OF A PIECE OF WIRE 60 METERS LONG AND 1.2 CENTIMETERS IN DIAMETER MADE FROM THE SAME MATERIAL? \n" ); document.write( "
Algebra.Com's Answer #43806 by uma(370)![]() ![]() ![]() You can put this solution on YOUR website! Let K be the constant of proportionality.\r \n" ); document.write( "\n" ); document.write( "Then r = K*l/(d^2) wher d is the diameter.\r \n" ); document.write( "\n" ); document.write( "Given that a wire of length 20 m and diameter 0.6 cm has a resistance of 36 ohms\r \n" ); document.write( "\n" ); document.write( "==> 36 = K* 2000/((0.6)^2)\r \n" ); document.write( "\n" ); document.write( "==> 36 = K*2000/(0.36)\r \n" ); document.write( "\n" ); document.write( "Multiplying both the sides by 0.36/2000 we get,\r \n" ); document.write( "\n" ); document.write( "36*(0.36/2000) = K\r \n" ); document.write( "\n" ); document.write( "==> 0.00648 = K\r \n" ); document.write( "\n" ); document.write( "Now the equation for resistance becomes,\r \n" ); document.write( "\n" ); document.write( "r = 0.00648*l/(d^2) \r \n" ); document.write( "\n" ); document.write( "When l = 6000cm and d = 1.2 cm\r \n" ); document.write( "\n" ); document.write( "r = 0.00648 *(6000/(1.2)^2\r \n" ); document.write( "\n" ); document.write( "==> r = 0.00648 * (6000/1.44)\r \n" ); document.write( "\n" ); document.write( "==> r = 27\r \n" ); document.write( "\n" ); document.write( "Thus the resistance of 20 m long wire with diameter 1.2cm is 27 ohms.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Good Luck!!! \n" ); document.write( " |