document.write( "Question 62965: How many gallons of a 20% ammonia solution must be mixed with a 5% ammonia solution to create 20 gallons of 11% ammonia solution? \n" ); document.write( "
Algebra.Com's Answer #43802 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! How many gallons of a 20% ammonia solution must be mixed with a 5% ammonia solution to create 20 gallons of 11% ammonia solution? \n" ); document.write( "Let \"x\" be amount of 20% solution; amount of ammonia is 0.2x gallons \n" ); document.write( "The \"20-x\" is amount of 5% solution: amount of ammonia is \n" ); document.write( "0.05(20-x)=0.1-0.02x gallons \n" ); document.write( "Amount of mixture is 20 gallons: amount of ammonia in it is 0.11(20)=2.2 gallons \n" ); document.write( "----------- \n" ); document.write( "EQUATION: \n" ); document.write( "ammonia + ammonia = ammonia \n" ); document.write( "0.2x + 0.1-0.02x=2.2 \n" ); document.write( "Multiply thru by 100 to get: \n" ); document.write( "20x+10-2x=220 \n" ); document.write( "18x=210 \n" ); document.write( "x= 11 2/3 gallons (amount of 20% solution) \n" ); document.write( "20-x= 8 1/3 gallons (amount of 5% solution) \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |