document.write( "Question 712452: what are three consecutive odd integers whose sum is equal to five more than two times the second largest number among the three numbers. \n" ); document.write( "
Algebra.Com's Answer #438004 by algebrahouse.com(1659)![]() ![]() You can put this solution on YOUR website! x = first \n" ); document.write( "x + 2 = second \n" ); document.write( "x + 4 = third {odd integers increase by 2 each time}\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x + x + 2 + x + 4 = 2(x + 2) + 5 {sum is five more than two times second largest} \n" ); document.write( "3x + 6 = 2x + 4 + 5 {used distributive property and combined like terms} \n" ); document.write( "3x + 6 = 2x + 9 {combined like terms on right side} \n" ); document.write( "x = 3 {subtracted 2x and subtracted 6 from each side} \n" ); document.write( "x + 2 = 5 {substituted 5, in for x, into x + 2} \n" ); document.write( "x + 4 = 7 {substituted 3, in for x, into x + 4}\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "3,5, and 7 are the three consecutive odd integers \n" ); document.write( " For more help from me, visit: www.algebrahouse.com \n" ); document.write( " |