document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=712498>Question 712498</A>: <I><SPAN STYLE=\"word-break: break-all;\"> For f(x)= 1/2x, determine f(1) - f(3)  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #437977 by </B><A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><B>algebrahouse.com(1659)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=algebrahouse.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=437977\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> f(x) = (1/2)x\r<BR>\n" );
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document.write( "f(1) <BR>\n" );
document.write( "= (1/2)(1)   {substituted 1 for x}<BR>\n" );
document.write( "= 1/2 {multiplied}\r<BR>\n" );
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document.write( "f(3)<BR>\n" );
document.write( "= (1/2)(3) {substituted 3 for x}<BR>\n" );
document.write( "= 3/2 {multiplied}\r<BR>\n" );
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document.write( "1/2 - 3/2 {value of f(1) - value of f(3)}<BR>\n" );
document.write( "= -2/2 {subtracted numerators over common denominator}<BR>\n" );
document.write( "= -1 {reduced}\r<BR>\n" );
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document.write( "f(1) - f(3) = -1<BR>\n" );
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