document.write( "Question 712367: why is
\n" ); document.write( "the sum of our age we are currently and the year we were born all add up too 113
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Algebra.Com's Answer #437971 by KMST(5328)\"\" \"About 
You can put this solution on YOUR website!
I can tell that you recently had a birthday and are older than 13.
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\n" ); document.write( "Let \"x\" be the year you were born (with all four digits for the year).
\n" ); document.write( "People born before 2000 are used to naming the year they were born with just 2 digits, as in 93 for 1992. That two-digit number would be
\n" ); document.write( "\"y=x-1990\" <--> \"x=1990%2By\"
\n" ); document.write( "We are in the year 2013, and today is February 9 where I live.
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\n" ); document.write( "If you were born in January, or early in the month of February (before the 10th),
\n" ); document.write( "you recently had a birthday and your age is \"2013-x\" or \"2013-%281990%2By%29=2013-1990-y=113-y\"
\n" ); document.write( "Then adding your age, and the year you were born you get
\n" ); document.write( "\"%282013-x%29%2Bx=2013%29\" or \"%28113-y%29%2By=113\"
\n" ); document.write( "depending on how you name the year you were born.
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\n" ); document.write( "However, if your birthdat is in late February (like mine), or later yet,
\n" ); document.write( "you would count your age as
\n" ); document.write( "\"2012-x\" or \"112-y\".
\n" ); document.write( "In that case, the sum would be
\n" ); document.write( "\"%282012-x%29%2Bx=2012\" or \"%28112-y%29%2By=112\"
\n" ); document.write( "That is what I get for my sum,
\n" ); document.write( "and so would a little over 89.0%=\"325%2F365\" of
\n" ); document.write( "the people.
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