document.write( "Question 62959: Solve log(x) + log(x-3)=1 \n" ); document.write( "

Algebra.Com's Answer #43797 by stanbon(75887) $\"\"$ $\"About$

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Solve log(x) + log(x-3)=1
\n" ); document.write( "log[x(x-3)]=1
\n" ); document.write( "x^2-3x=10^1
\n" ); document.write( "x^2-3x-10=0
\n" ); document.write( "(x-5)(x+2)=0
\n" ); document.write( "x=5 or x=-2
\n" ); document.write( "x-2 is an extraneous solution
\n" ); document.write( "because log(-2) does not exist.
\n" ); document.write( "Final Solution: x=5
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H. \n" ); document.write( "

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