document.write( "Question 712482: 3x/ (x^2+5x+6) = 5x/ (x^2+2x-3) - 2/(x^2+x-2) \n" ); document.write( "
Algebra.Com's Answer #437968 by lynnlo(4176)\"\" \"About 
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3x(x-1)=5x(x+2)-2(x+3)
\n" ); document.write( "3x(x-1)-5x(x+2)+2(x+3)=0
\n" ); document.write( "-2x^2-11x+6=0
\n" ); document.write( "-((x+6)(2x-1))=0
\n" ); document.write( "(x+6)(2x-1)=0
\n" ); document.write( "x+6=0 OR 2x-1=0
\n" ); document.write( "x=-6 OR 2x-1=0
\n" ); document.write( "x=-6 OR 2x=1
\n" ); document.write( "DIVIDE BOTH SIDES BY 2
\n" ); document.write( " x=-6 OR x=1/2
\n" ); document.write( "
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