document.write( "Question 62960: Solve ln(2x-1)-ln(4)=ln(x-2) \n" ); document.write( "
Algebra.Com's Answer #43796 by stanbon(75887)\"\" \"About 
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Solve ln(2x-1)-ln(4)=ln(x-2)
\n" ); document.write( "ln(2x-1)=ln[4/(x-2)]
\n" ); document.write( "2x-1 = 4/(x-2)
\n" ); document.write( "2x^2-4x-x+2=-4
\n" ); document.write( "2x^2-5x+6=0
\n" ); document.write( "x=[5+-sqrt(25-4(2)(6))]/4
\n" ); document.write( "x=[5+-1]/4
\n" ); document.write( "x=3/2 or x=1
\n" ); document.write( "Both solution are extraneous:
\n" ); document.write( "If x=3/2, ln(x-2)=ln(-1/2) which does not exist.
\n" ); document.write( "If x=1, ln(x-2)=ln(-1) which does not exist.
\n" ); document.write( "Conclusion: No solution
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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