document.write( "Question 712446: \"+sqrt+%28b%29-6=-2%2A+sqrt%28b%29+\"
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Algebra.Com's Answer #437951 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
Square both sides and simplify. Square again both sides and simplify again. \r
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\n" ); document.write( "\n" ); document.write( "The situation you were given is based on having summable irrational numbers, so you can't simply bring them together as factors. \r
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\n" ); document.write( "\n" ); document.write( "\"+sqrt+%28b%29-6=-2%2A+sqrt%28b%29+\"
\n" ); document.write( "b-12*sqrt(b)+36=4*b
\n" ); document.write( "\"-12%2Asqrt%28b%29=4b-36-b\"
\n" ); document.write( "\"12%2Asqrt%28b%29=b-4b%2B36\"
\n" ); document.write( "\"12%2Asqrt%28b%29=36-3b\"
\n" ); document.write( "\"12%2Asqrt%28b%29=3%2812-b%29\"
\n" ); document.write( "\"4%2Asqrt%28b%29=12-b\"\r
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\n" ); document.write( "\n" ); document.write( "\"16%2Ab=144-24b%2Bb%5E2\"
\n" ); document.write( "\"highlight%28b%5E2-40b%2B144=0%29\"\r
\n" ); document.write( "\n" ); document.write( "Using general solution to quadratic formula, to avoid looking for factoring the trinomial, b=4 or b=36; but you should test to see if both of these will work in the original equation.
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