document.write( "Question 712355: Candy, a confectioner, has a 9 pound bag of mixed candy that contains 20% chocolate. How many pounds should she remove from the bag so that when she adds just chocolate to the bag, she'll have a mixture that contains 50% chocolate?\r
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document.write( "I've determined the variable as x which equals pounds removed but not sure where to go from here? \n" );
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Algebra.Com's Answer #437884 by josgarithmetic(39617)![]() ![]() ![]() You can put this solution on YOUR website! Candy starts with 9 pounds mixture * 0.20 fraction chocolate = 1.8 pounds of chocolate. She will remove x pounds of this 0.20 fraction chocolate, add x pounds of pure chocolate, still have 9 pounds of mixture, and this now be 50% chocolate.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "That value is worth checking. It does work. Yes I did check. \n" ); document.write( " |