document.write( "Question 712355: Candy, a confectioner, has a 9 pound bag of mixed candy that contains 20% chocolate. How many pounds should she remove from the bag so that when she adds just chocolate to the bag, she'll have a mixture that contains 50% chocolate?\r
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Algebra.Com's Answer #437884 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
Candy starts with 9 pounds mixture * 0.20 fraction chocolate = 1.8 pounds of chocolate. She will remove x pounds of this 0.20 fraction chocolate, add x pounds of pure chocolate, still have 9 pounds of mixture, and this now be 50% chocolate.\r
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\n" ); document.write( "\n" ); document.write( "\"%289%2A0.20-0.20x%2B1%2Ax%29%2F9=0.50\", check this carefully to know how the numbers work. I'm using decimal values instead of percents.\r
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\n" ); document.write( "\n" ); document.write( "\"0.2%2A9%2B0.8%2Ax=9%2A0.50\"
\n" ); document.write( "\"x=9%280.5-0.2%29%2F0.8\"
\n" ); document.write( "\"x=9%283%2F8%29\"
\n" ); document.write( "\"x=27%2F8\"
\n" ); document.write( "\"x=3%263%2F8\" pounds\r
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\n" ); document.write( "\n" ); document.write( "That value is worth checking. It does work. Yes I did check.
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