document.write( "Question 712321: log base 3(2x+3) + log base 3 (X-2)=log base 3 72 what would the answer be in traditional \n" ); document.write( "
Algebra.Com's Answer #437864 by nerdybill(7384)\"\" \"About 
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log base 3(2x+3) + log base 3 (X-2)=log base 3 72
\n" ); document.write( "log base 3(2x+3)(X-2)=log base 3 72
\n" ); document.write( "(2x+3)(X-2)= 72
\n" ); document.write( "2x^2-4x+3x-6=72
\n" ); document.write( "2x^2-x-6=72
\n" ); document.write( "2x^2-x-78=0
\n" ); document.write( "rewrite the middle term:
\n" ); document.write( "2x^2+12x-13x-78=0
\n" ); document.write( "(2x^2+12x)-(13x+78)=0
\n" ); document.write( "2x(x+6)-13(x+6)=0
\n" ); document.write( "(x+6)(2x-13) = 0
\n" ); document.write( "x = {-6, 13/2}
\n" ); document.write( "throw out the negative solution (extraneous) leaving:
\n" ); document.write( "x = 13/2
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