document.write( "Question 712304: Showing work, solve the equation.
\n" ); document.write( "log a (x-8)-log a (x+4)=log a (x-3)- log a (x-2)\r
\n" ); document.write( "\n" ); document.write( "note: the a in this problem is smaller and sits lower.
\n" ); document.write( "thank you.
\n" ); document.write( "

Algebra.Com's Answer #437861 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "=\"log+%28a%2C%28%28x-8%29%2F%28x%2B4%29%29%29=log%28+a%2C%28%28x-3%29%2F%28x-2%29%29%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "=\"%28x-8%29%2F%28x%2B4%29=%28x-3%29%2F%28x-2%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "=\"%28x-8%29%28x-2%29=%28x-3%29%28x%2B4%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "=\"x%5E2-2x-8x%2B16=x%5E2%2B4x-3x-12\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "=\"-10x%2B16=x-12\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "=\"12%2B16=10x%2Bx\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "=\"28=11x\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "=\"28%2F11=x\"\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );