document.write( "Question 712268: If m and p are positive integers and (m+p) x m is even, which of the following must be true. A)if m is odd, then p is odd B)if m is odd, then p is even C)if m is even, then p is even D)if m is even, then p is odd. \n" ); document.write( "
Algebra.Com's Answer #437845 by jim_thompson5910(35256)\"\" \"About 
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(m+p) x m is even \r
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\n" ); document.write( "\n" ); document.write( "so either m is even or m+p is even\r
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\n" ); document.write( "\n" ); document.write( "If m is even, then m+p is odd only if p is odd.\r
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\n" ); document.write( "\n" ); document.write( "If m+p is even, then \r
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\n" ); document.write( "\n" ); document.write( "a) both m and p are even (since even + even = even)\r
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\n" ); document.write( "\n" ); document.write( "or\r
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\n" ); document.write( "\n" ); document.write( "b) both m and p are odd (since odd + odd = even)\r
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\n" ); document.write( "\n" ); document.write( "So let's go through the choices\r
\n" ); document.write( "\n" ); document.write( "A)if m is odd, then p is odd \r
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\n" ); document.write( "\n" ); document.write( "This is true because m+p is even if both m and p are odd and m+p must be even for (m+p) x m to be even (since m is odd)\r
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\n" ); document.write( "\n" ); document.write( "B)if m is odd, then p is even \r
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\n" ); document.write( "\n" ); document.write( "This is false because it's the complete opposite of choice A which was true.\r
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\n" ); document.write( "\n" ); document.write( "C)if m is even, then p is even \r
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\n" ); document.write( "\n" ); document.write( "If m is even, then (m+p) x m is even (since even x odd = odd x even = even x even = even)\r
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\n" ); document.write( "\n" ); document.write( "So because p could be even or odd (it wouldn't change the outcome), we can't say for sure if p is even\r
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\n" ); document.write( "\n" ); document.write( "So this is false\r
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\n" ); document.write( "\n" ); document.write( "D)if m is even, then p is odd.\r
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\n" ); document.write( "\n" ); document.write( "Using the same logic above, we can't determine if p is odd when m is even. So there's no way of knowing.\r
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\n" ); document.write( "\n" ); document.write( "So this is false too.
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