document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=712251>Question 712251</A>: <I><SPAN STYLE=\"word-break: break-all;\"> \r<BR>\n" );
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document.write( "Three times one number added to five times a second number is 68.  Three times the second number minus four times the first number is 6.  What are the two numbers? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #437840 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley79><B>checkley79(3341)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley79><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=437840\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3X+5Y=68 MULTIPLY BY 4<BR>\n" );
document.write( "3Y-4X=6 MULTIPLY BY 3 & ADD.<BR>\n" );
document.write( "12X+20Y=272<BR>\n" );
document.write( "-12X+9Y=18<BR>\n" );
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document.write( "29Y=290<BR>\n" );
document.write( "Y=290/29<BR>\n" );
document.write( "Y=10 ANS.<BR>\n" );
document.write( "3X+5*10=68<BR>\n" );
document.write( "3X+50=68<BR>\n" );
document.write( "3X=68-50<BR>\n" );
document.write( "3X=18<BR>\n" );
document.write( "X=18/3<BR>\n" );
document.write( "X=6 ANS.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "3*10-4*6=6 <BR>\n" );
document.write( "30-24=6<BR>\n" );
document.write( "6=6 </SPAN>\n" );
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