document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=712186>Question 712186</A>: <I><SPAN STYLE=\"word-break: break-all;\"> y^2/3 + 2y^1/3 -3 = 0\r<BR>\n" );
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document.write( "Solve For Y </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #437815 by </B><A HREF=/tutors/aboutme.mpl?userid=htmentor><B>htmentor(1343)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=htmentor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=htmentor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=437815\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x = y^1/3<BR>\n" );
document.write( "Then we can write the equation as<BR>\n" );
document.write( "x^2 + 2x - 3 = 0<BR>\n" );
document.write( "This can be factored as<BR>\n" );
document.write( "(x-1)(x+3) = 0<BR>\n" );
document.write( "The solutions are x=1, x=-3<BR>\n" );
document.write( "So we have y^1/3 = 1 and y^1/3 = -3<BR>\n" );
document.write( "y^1/3 = 1 -> y = (1)^3 = 1<BR>\n" );
document.write( "y^1/3 = -3 -> y = (-3)^3 = -27<BR>\n" );
document.write( "Ans: y=1, y=-27  </SPAN>\n" );
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