document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=712167>Question 712167</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find three consecutive odd integers such that twice the first is 7 more than the third </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #437801 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39620)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=437801\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Start this way:\r<BR>\n" );
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document.write( "The numbers are: 2n+1, 2n+3, 2n+5\r<BR>\n" );
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document.write( "2(2n+1)=7+2n+5\r<BR>\n" );
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document.write( "First solve for n.  Then compute each of the three numbers. </SPAN>\n" );
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