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document.write( "The perimeter of a rectangular garden is 40yd, and its area is 36yd^2. How many yards long is the longest side of the garden? (yd^2 = Square Feet) \n" );
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Algebra.Com's Answer #437755 by checkley79(3341)![]() ![]() ![]() You can put this solution on YOUR website! P=2L+2W \n" ); document.write( "A=LW \n" ); document.write( "36=LW \n" ); document.write( "L=36/W \n" ); document.write( "40=2(36/W)+2W \n" ); document.write( "40=72/W+2W \n" ); document.write( "40=(72+2W*W)/W \n" ); document.write( "40=(72+2W^2)/W \n" ); document.write( "40W=2W^2+72 \n" ); document.write( "2W^2-40W+72=0 \n" ); document.write( "2(W^2-20W+36)=0 \n" ); document.write( "2(W-18)(W-2)=0 \n" ); document.write( "W-18=0 \n" ); document.write( "W=18 ANS. \n" ); document.write( "L=36/18=2 ANS. \n" ); document.write( "W-2=0 \n" ); document.write( "W=2 ANS. \n" ); document.write( "################ \n" ); document.write( "L=36/2 \n" ); document.write( "L=18 ANS. \n" ); document.write( " \n" ); document.write( " |