document.write( "Question 712102: \r
\n" ); document.write( "\n" ); document.write( "How many liters of 40% glycerin solution must be mixed with 10 liters of 80% glycerin to obtain 65% glycerin solution?
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Algebra.Com's Answer #437751 by checkley79(3341)\"\" \"About 
You can put this solution on YOUR website!
.80*10+.40X=.65(X+10)
\n" ); document.write( "8+.40X=.65X+6.5
\n" ); document.write( ".40X-.65X=6.5-8
\n" ); document.write( "-.25X=-1.5
\n" ); document.write( "X=-1.5/-.25
\n" ); document.write( "X=6 LITERS OF 80$ SOLUTION IS USED.
\n" ); document.write( "PROOF:
\n" ); document.write( ".80*10+.40*6=.65(6+10)
\n" ); document.write( "8+2.4=.65*16
\n" ); document.write( "10.4=10.4
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