document.write( "Question 712055: how much distilled water must be added to 4 pints of 65% alcohol to make a mixture of 50% alcohol \n" ); document.write( "
Algebra.Com's Answer #437740 by josgarithmetic(39617)![]() ![]() ![]() You can put this solution on YOUR website! All volumes will be as pints. The information given also suggests concentrations are %volume/volume. My solution (answer) assumes that. The water contains 0% alcohol. \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "P= 65% \n" ); document.write( "T= 50% \n" ); document.write( "V= 4 pints \n" ); document.write( "v = unknown volume to add\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Equation: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Substitute the values: \n" ); document.write( " \n" ); document.write( " |