document.write( "Question 712055: how much distilled water must be added to 4 pints of 65% alcohol to make a mixture of 50% alcohol \n" ); document.write( "
Algebra.Com's Answer #437740 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
All volumes will be as pints. The information given also suggests concentrations are %volume/volume. My solution (answer) assumes that. The water contains 0% alcohol. \r
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\n" ); document.write( "\n" ); document.write( "P= 65%
\n" ); document.write( "T= 50%
\n" ); document.write( "V= 4 pints
\n" ); document.write( "v = unknown volume to add\r
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\n" ); document.write( "\n" ); document.write( "Equation:
\n" ); document.write( "\"V%2AP%2F%28v%2BV%29=T\"
\n" ); document.write( "\"V%2AP=%28Tv%2BTV%29\"
\n" ); document.write( "\"V%2AP=Tv%2BTV\"
\n" ); document.write( "\"Tv=VP-TV\"
\n" ); document.write( "\"highlight%28v=V%28P-T%29%2FT%29\"\r
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\n" ); document.write( "\n" ); document.write( "Substitute the values:
\n" ); document.write( "\"v=%284%2A65-50%2A4%29%2F50\"=60/50
\n" ); document.write( "\"v=1%261%2F5\" pints
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