document.write( "Question 712086: find the range of values which the line y=kx+3 meets the curve xy+20=5y \n" ); document.write( "
Algebra.Com's Answer #437739 by josgarithmetic(39617)\"\" \"About 
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You should be able to substitute y=kx+3 into xy+20=5y and solve for k. That should help to find \"kx%5E2%2B3%281-5k%29x%2B5=0\". Knowledge of the general solution to a quadratic equation suggests k must not be zero.\r
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\n" ); document.write( "\n" ); document.write( "Carry out the steps you find \"x=%28-3%281-5k%29-sqrt%28225k%5E2-110k%2B9%29%29%2F%282k%29\"
\n" ); document.write( "or \"x=%28-3%281-5k%29%2Bsqrt%28225k%5E2-110k%2B9%29%29%2F%282k%29\"\r
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\n" ); document.write( "\n" ); document.write( "From that you may want to be sure to know how the discriminant should be greater than or equal to zero. Solve \"225k%5E2-110k%2B9%3E=0\". Again use solution to quadratic equation:\r
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\n" ); document.write( "\n" ); document.write( "\"k=%2811-2%2Asqrt%2810%29%29%2F45\" or \"k=%2811%2B2%2Asqrt%2810%29%29%2F45\" But those values should be first checked as critical points. The k quadratic should be greater than OR EQUAL TO ZERO. There are three intervals of k to check the discriminant expression as \"225k%5E2-110k%2B9%3E=0\".\r
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\n" ); document.write( "\n" ); document.write( "Pushing ahead according to testing k in those intervals, the critical points in decimalized form would be close to k at 0.10389 and at 0.385. I picked to check values 0, 0.2, and 0.4. The results of the expression>=0 went like this:\r
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\n" ); document.write( "\n" ); document.write( "at 0: \"9%3E=0\", yes.
\n" ); document.write( "at 0.2: \"-4%3E=0\", no.
\n" ); document.write( "at 0.4: \"1%3E=0\", yes.\r
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\n" ); document.write( "\n" ); document.write( "Based on that, it seems k should be this:\r
\n" ); document.write( "\n" ); document.write( "\"k%3C=%2811-2%2Asqrt%2810%29%29%2F45\"
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\n" ); document.write( "\"k%3E=%2811%2B2%2Asqrt%2810%29%29%2F45\"\r
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\n" ); document.write( "\n" ); document.write( "This was based on expecting complex values of k to cause lack of meaningful solutions to the original set of equations.
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