document.write( "Question 711863: im trying to do x^2+9x+18 and I've tried to do 9(x+x)2+18 and (x+x)^2(9+18) \n" ); document.write( "
Algebra.Com's Answer #437667 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "Looking at the expression \"x%5E2%2B9x%2B18\", we can see that the first coefficient is \"1\", the second coefficient is \"9\", and the last term is \"18\".\r
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\n" ); document.write( "\n" ); document.write( "Now multiply the first coefficient \"1\" by the last term \"18\" to get \"%281%29%2818%29=18\".\r
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\n" ); document.write( "\n" ); document.write( "Now the question is: what two whole numbers multiply to \"18\" (the previous product) and add to the second coefficient \"9\"?\r
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\n" ); document.write( "\n" ); document.write( "To find these two numbers, we need to list all of the factors of \"18\" (the previous product).\r
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\n" ); document.write( "\n" ); document.write( "Factors of \"18\":\r
\n" ); document.write( "\n" ); document.write( "1,2,3,6,9,18\r
\n" ); document.write( "\n" ); document.write( "-1,-2,-3,-6,-9,-18\r
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\n" ); document.write( "\n" ); document.write( "Note: list the negative of each factor. This will allow us to find all possible combinations.\r
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\n" ); document.write( "\n" ); document.write( "These factors pair up and multiply to \"18\".\r
\n" ); document.write( "\n" ); document.write( "1*18 = 18
\n" ); document.write( "2*9 = 18
\n" ); document.write( "3*6 = 18
\n" ); document.write( "(-1)*(-18) = 18
\n" ); document.write( "(-2)*(-9) = 18
\n" ); document.write( "(-3)*(-6) = 18\r
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\n" ); document.write( "\n" ); document.write( "Now let's add up each pair of factors to see if one pair adds to the middle coefficient \"9\":\r
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First NumberSecond NumberSum
1181+18=19
292+9=11
363+6=9
-1-18-1+(-18)=-19
-2-9-2+(-9)=-11
-3-6-3+(-6)=-9
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\n" ); document.write( "\n" ); document.write( "From the table, we can see that the two numbers \"3\" and \"6\" add to \"9\" (the middle coefficient).\r
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\n" ); document.write( "\n" ); document.write( "So the two numbers \"3\" and \"6\" both multiply to \"18\" and add to \"9\"\r
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\n" ); document.write( "\n" ); document.write( "Now replace the middle term \"9x\" with \"3x%2B6x\". Remember, \"3\" and \"6\" add to \"9\". So this shows us that \"3x%2B6x=9x\".\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2%2Bhighlight%283x%2B6x%29%2B18\" Replace the second term \"9x\" with \"3x%2B6x\".\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%5E2%2B3x%29%2B%286x%2B18%29\" Group the terms into two pairs.\r
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\n" ); document.write( "\n" ); document.write( "\"x%28x%2B3%29%2B%286x%2B18%29\" Factor out the GCF \"x\" from the first group.\r
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\n" ); document.write( "\n" ); document.write( "\"x%28x%2B3%29%2B6%28x%2B3%29\" Factor out \"6\" from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%2B6%29%28x%2B3%29\" Combine like terms. Or factor out the common term \"x%2B3\"\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So \"x%5E2%2B9x%2B18\" factors to \"%28x%2B6%29%28x%2B3%29\".\r
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\n" ); document.write( "\n" ); document.write( "In other words, \"x%5E2%2B9x%2B18=%28x%2B6%29%28x%2B3%29\".\r
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\n" ); document.write( "\n" ); document.write( "Note: you can check the answer by expanding \"%28x%2B6%29%28x%2B3%29\" to get \"x%5E2%2B9x%2B18\" or by graphing the original expression and the answer (the two graphs should be identical).
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