document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=711811>Question 711811</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A landscaping company needs 200 gallons of 24% fertilizer to fertilize the shrubs in an office park. They have in stock 30% fertilizer and 20% fertilizer. How much of each type should they mix together? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #437636 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=437636\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A landscaping company needs 200 gallons of 24% fertilizer to fertilize the shrubs in an office park. They have in stock 30% fertilizer and 20% fertilizer. How much of each type should they mix together?<BR>\n" );
document.write( "**<BR>\n" );
document.write( "let x=amt of 30% fertilizer to mix<BR>\n" );
document.write( "200-x=amt of 20% fertilizer to mix<BR>\n" );
document.write( "30%x+20%(200-x)=24%*200<BR>\n" );
document.write( ".3x+40-.2x=48<BR>\n" );
document.write( "0.x=8<BR>\n" );
document.write( "x=80<BR>\n" );
document.write( "200-x=120<BR>\n" );
document.write( "amt of 30% fertilizer to mix=80 gal<BR>\n" );
document.write( "amt of 20% fertilizer to mix=120 gal </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );