document.write( "Question 711756: If you drove for 30 minutes at 60 mph and 10 minutes at 38 mph. What was your average speed for the trip? \n" ); document.write( "
Algebra.Com's Answer #437617 by Edwin McCravy(20059)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "The other tutor used decimals and rounded off, making his answer off\r\n" );
document.write( "a little.  I'll use fractions.\r\n" );
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document.write( "We use two formulas:\r\n" );
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document.write( "Distance = Rate × Time\r\n" );
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document.write( "Average Rate = Total Distance ÷ Total Time\r\n" );
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document.write( "When you went 30 minutes (half an hour) at 60 mph,\r\n" );
document.write( "you went 60×\"1%2F2\" = 30 miles  \r\n" );
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document.write( "When you went 10 minutes (\"1%2F6\" of an hour) at 38 mph,\r\n" );
document.write( "you went 38×\"1%2F6\" = \"38%2F6\" =  \"19%2F3\" = \"6%261%2F3\" miles \r\n" );
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document.write( "To find the total distance, we use the improper fraction for\r\n" );
document.write( "the distance at 38 mph \r\n" );
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document.write( "Total distance = \"30\"\"%22%22%2B%22%22\"\"19%2F3\"\"%22%22=%22%22\"\"90%2F3\"\"%22%22%2B%22%22\"\"19%2F3\"\"%22%22=%22%22\"\"109%2F3\" or \"36%261%2F3\" miles.\r\n" );
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document.write( " Total time = \"1%2F2\"\"%22%22%2B%22%22\"\"1%2F6\"\"%22%22=%22%22\"\"3%2F6\"\"%22%22%2B%22%22\"\"1%2F6\"\"%22%22=%22%22\"\"4%2F6\" or \"2%2F3\" hr.\r\n" );
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document.write( "Average Rate = Total Distance ÷ Total Time\r\n" );
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document.write( "We will use the improper fraction for the total miles  \r\n" );
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document.write( "Average Rate = \"109%2F3\"÷\"2%2F3\"\"%22%22=%22%22\"\"109%2F3\"\"%22%22%2A%22%22\"\"3%2F2\"\"%22%22=%22%22\"\"109%2Fcross%283%29\"\"%22%22%2A%22%22\"\"cross%283%29%2F2\"\"%22%22=%22%22\"\"109%2F2\"\"%22%22=%22%22\"\"54%261%2F2\"mph.\r\n" );
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document.write( "Edwin

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