document.write( "Question 711751: \r
\n" ); document.write( "\n" ); document.write( "Solve by factoring:\r
\n" ); document.write( "\n" ); document.write( "y2 + 2y = 8
\n" ); document.write( " please PLEASE help me and please show your work.
\n" ); document.write( "thank you so much
\n" ); document.write( "~April
\n" ); document.write( "

Algebra.Com's Answer #437573 by tutor_paul(519)\"\" \"About 
You can put this solution on YOUR website!
\"y%5E2%2B2y=8\"
\n" ); document.write( "First step is to equate to zero. Do this by adding -8 to both sides of the equation:
\n" ); document.write( "\"y%5E2%2B2y-8=8-8\"
\n" ); document.write( "Simplify:
\n" ); document.write( "\"y%5E2%2B2y-8=0\"
\n" ); document.write( "Now you can factor this. You have to think to yourself \"What factors of -8, when combined, add up to 2?\" Well, -2 and 4 come to mind. Use these as the factors:
\n" ); document.write( "\"%28y%2B4%29%28y-2%29=0\"
\n" ); document.write( "Now you equate each term to zero and solve for y:
\n" ); document.write( "\"y%2B4=0\"
\n" ); document.write( "\"highlight%28y=-4%29\"
\n" ); document.write( "\"y-2=0\"
\n" ); document.write( "\"highlight%28y=2%29\"
\n" ); document.write( "===================
\n" ); document.write( "Good Luck,
\n" ); document.write( "tutor_paul@yahoo.com
\n" ); document.write( "
\n" );