document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=711679>Question 711679</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I was wondering how would you solve a linear system using subsitution? My teacher taught the class this in like 10 min and I'm not sure.. Can you show me to steps to answer -x+2y=-6 and 8x+y=31 thanks! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #437561 by </B><A HREF=/tutors/aboutme.mpl?userid=lynnlo><B>lynnlo(4176)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lynnlo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=437561\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> -X+2Y=-6<BR>\n" );
document.write( "8X+Y=3<BR>\n" );
document.write( "STEP (1)MULTIPLY FIRST EQUATION BY 8<BR>\n" );
document.write( "AFTER YOU MULTIPLY YOU WILL HAVE <BR>\n" );
document.write( "-8X+16Y=-48<BR>\n" );
document.write( "8X+Y=3<BR>\n" );
document.write( "STEP (2)ADD THE TWO EQUATIONS TOGETHER TO ELIMINATE X <BR>\n" );
document.write( "17Y=-45<BR>\n" );
document.write( "STEP(3) FIND Y<BR>\n" );
document.write( "Y=-45/17<BR>\n" );
document.write( "STEP (4)SUBSTITUTE THE VALUE FOR Y INTO THE ORIGINAL EQUATION TO SOLVE X<BR>\n" );
document.write( "-X+2(-45/17)=-6<BR>\n" );
document.write( "X=12/17<BR>\n" );
document.write( "Y=-45/17 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );