document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=711679>Question 711679</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I was wondering how would you solve a linear system using subsitution? My teacher taught the class this in like 10 min and I'm not sure.. Can you show me to steps to answer -x+2y=-6 and 8x+y=31 thanks! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #437543 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=437543\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> -x+2y=-6 <BR>\n" );
document.write( "8x+ y=31<BR>\n" );
document.write( "-------------<BR>\n" );
document.write( "You have a choice: solve the 1st equation for \"x\"<BR>\n" );
document.write( "or solve the 2nd equation for \"y\":<BR>\n" );
document.write( "-----<BR>\n" );
document.write( "Solving for x you get:<BR>\n" );
document.write( "x = 2y+6<BR>\n" );
document.write( "----<BR>\n" );
document.write( "Substitute for \"x\" in the 2nd equation and solve for \"y\":<BR>\n" );
document.write( "8(2y+6)+y = 31<BR>\n" );
document.write( "16y + 48 + y = 31<BR>\n" );
document.write( "17y = -17<BR>\n" );
document.write( "y = -1<BR>\n" );
document.write( "-----------<BR>\n" );
document.write( "Solve for \"x\" using x = 2y+6<BR>\n" );
document.write( "x = 2*-1+6<BR>\n" );
document.write( "x = 4<BR>\n" );
document.write( "====================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "====================  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );