document.write( "Question 711655: \r
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\n" ); document.write( "\n" ); document.write( "when 2 inches are added to each side of a square its area increase by 44 square inches. what was the perimeter of the initial square?
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Algebra.Com's Answer #437516 by checkley79(3341)\"\" \"About 
You can put this solution on YOUR website!
(X+2)^2=X^2+44
\n" ); document.write( "X^2+4X+4=X^2+44
\n" ); document.write( "X^2-X^2+4X=44-4
\n" ); document.write( "4X=40
\n" ); document.write( "X=40/4
\n" ); document.write( "X=10 INCHES FOR THE ORIGINAL SIDE OF THE SQUARE.
\n" ); document.write( "PROOF:
\n" ); document.write( "(10+2)^2=10^2+44
\n" ); document.write( "12^2=144
\n" ); document.write( "144=144\r
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