document.write( "Question 711594: Twenty ounces of pure silver are added to 70 oz of a silver alloy that is 10% silver. What is the percent concentration of the resulting alloy? \n" ); document.write( "

Algebra.Com's Answer #437463 by josgarithmetic(39617) $\"\"$ $\"About$

You can put this solution on YOUR website!
Pure silver is 100% silver.\r
\n" ); document.write( "\n" ); document.write( "There are high percent silver and lower percent silver and the mixture will make some intermediate percent silver, T.\r
\n" ); document.write( "\n" ); document.write( "T = the resulting % silver Unknown but will be found
\n" ); document.write( "H = 100, the pure silver 100%
\n" ); document.write( "L = 10, the 10% silver concentration
\n" ); document.write( "x = 70 ounces of 10% silver
\n" ); document.write( "y = 20 ounces of 100% silver.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Objective is find T. \r
\n" ); document.write( "\n" ); document.write( "Amount of silver = x*L+y*H
\n" ); document.write( "Amount of alloy = x+y\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " $\"T=%28x%2AL%2By%2AH%29%2F%28x%2By%29\"$ \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Use the given values:
\n" ); document.write( " $\"T=%2870%2A10%2B20%2A100%29%2F%2870%2B20%29\"$
\n" ); document.write( "T=30, so alloy resulting is 30% silver. \n" ); document.write( "

\n" );