document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=711495>Question 711495</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A father is four times as old as his son and his daughter is five years younger than her brother. If their combined age is 73 years, find the age of each. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #437443 by </B><A HREF=/tutors/aboutme.mpl?userid=rfer><B>rfer(16322)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rfer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=437443\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x=son<BR>\n" );
document.write( "4x=father<BR>\n" );
document.write( "x-5=daughter<BR>\n" );
document.write( "--------------<BR>\n" );
document.write( "x+4x+x-5=73<BR>\n" );
document.write( "6x=78<BR>\n" );
document.write( "x=78/6<BR>\n" );
document.write( "x=13<BR>\n" );
document.write( "4x=52<BR>\n" );
document.write( "x-5=8 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );