document.write( "Question 62820This question is from textbook beginning algebra
\n" ); document.write( ": 49. 9x-12y=18
\n" ); document.write( " 2y=-x+1\r
\n" ); document.write( "\n" ); document.write( "47. X+Y=1
\n" ); document.write( " 0.75X+0.5Y=2.21\r
\n" ); document.write( "\n" ); document.write( "When I tried to solve 47 according to the book my calulations are wrong the book ans is 6.84,-5.84 and for 49 the book ans is (8/5,-3/10 from both of these equation I got different ans. can you help me!!
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Algebra.Com's Answer #43742 by checkley71(8403)\"\" \"About 
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47) X+Y=1 THEN X=1-Y NOW SUBSTITUTE (1-Y) FOR X IN THE OTHER EQUATION THUS
\n" ); document.write( ".75(1-Y)+.5Y=2.21
\n" ); document.write( ".75-.75Y+.5Y=2.21
\n" ); document.write( "-.75Y+.5Y=2.21-.75
\n" ); document.write( "-.25Y=1.46
\n" ); document.write( "Y=1.46/-.25
\n" ); document.write( "Y=-5.84 SOLUTION.
\n" ); document.write( "NOW SUBSTITUTE-5.84 FOR Y AND SOLVE FOR X
\n" ); document.write( "X-5.84=1
\n" ); document.write( "X=1+5.84
\n" ); document.write( "X=6.84 SOLUTION
\n" ); document.write( "--------------------------------------------------------------------
\n" ); document.write( "49) 2Y=-X+1
\n" ); document.write( "X=1-2Y NOW SUB (1-2Y) FOR X IN THE OTHER EQUATION THUS
\n" ); document.write( "9(1-2Y)-12Y=18
\n" ); document.write( "9-18Y-12Y=18
\n" ); document.write( "-30Y=9
\n" ); document.write( "Y=9/-30
\n" ); document.write( "Y=-3/10 SOLUTION
\n" ); document.write( "NO SUB -3/10 FOR Y AND SOLVE FOR X
\n" ); document.write( "2*-3/10=-X+1
\n" ); document.write( "-6/10=-X+1
\n" ); document.write( "X=1+6/10
\n" ); document.write( "X=16/10
\n" ); document.write( "X=8/5 SOLUTION \r
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