document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=711390>Question 711390</A>: <I><SPAN STYLE=\"word-break: break-all;\"> At a certain point in his life (time 3), Arnold had an age with the second digit being three and with the square of the first digit being his actual age reversed. Earlier in his life, (time 2) Arnold had a father who was twice as old as he was. Twenty five years prior to that (time 1) the ratio of Arnold’s age to his father’s age was one to three.<BR>\n" );
document.write( "Your tasks are to determine how old Arnold was at each of the 3 times identified in the problem:<BR>\n" );
document.write( "time 1,<BR>\n" );
document.write( "time 2, and<BR>\n" );
document.write( "time 3. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #437407 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=437407\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> At a certain point in his life (time 3), Arnold had an age with the second digit being three and with the square of the first digit being his actual age reversed.<BR>\n" );
document.write( "a = the 1st digit<BR>\n" );
document.write( "10a+3 = his age in time 3<BR>\n" );
document.write( "a^2 = 30+a<BR>\n" );
document.write( "a^2 - a - 30 = 0<BR>\n" );
document.write( "(a-6)(a+5) = 0<BR>\n" );
document.write( "the positive solution<BR>\n" );
document.write( "a = 6<BR>\n" );
document.write( "Therefore:<BR>\n" );
document.write( "63 = age in time 3<BR>\n" );
document.write( ":<BR>\n" );
document.write( "Earlier in his life, (time 2) Arnold had a father who was twice as old as he was.<BR>\n" );
document.write( "Earlier in life: F = 2A<BR>\n" );
document.write( ":<BR>\n" );
document.write( " Twenty five years prior to that (time 1) the ratio of Arnold’s age to his father’s age was one to three.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28A-25%29%2F%28F-25%29 ALIGN=MIDDLE  ALT=\"%28A-25%29%2F%28F-25%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1%2F3 ALIGN=MIDDLE  ALT=\"1%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Cross multiply<BR>\n" );
document.write( "F-25 = 3(A-25)<BR>\n" );
document.write( "F - 25 = 3A - 75<BR>\n" );
document.write( "Replace F with 2A<BR>\n" );
document.write( "2A - 25 = 3A - 75<BR>\n" );
document.write( "-25 + 75 = 3A - 2A<BR>\n" );
document.write( "50 = A<BR>\n" );
document.write( "Arnold is 50 yrs old and Dad was 100 in time 2<BR>\n" );
document.write( ":<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%2850-25%29%2F%28100-25%29 ALIGN=MIDDLE  ALT=\"%2850-25%29%2F%28100-25%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1%2F3 ALIGN=MIDDLE  ALT=\"1%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "A is 25 yrs old and Dad is 75 yrs old in time 1\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "<BR>\n" );
document.write( "<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Your tasks are to determine how old Arnold was at each of the 3 times identified in the problem:<BR>\n" );
document.write( "time 1, 25<BR>\n" );
document.write( "time 2, 50<BR>\n" );
document.write( "time 3, 63 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );