document.write( "Question 711404: How do I solve this problem?\r
\n" ); document.write( "\n" ); document.write( "x^3+3x^3-4x-12=0
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Algebra.Com's Answer #437398 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
How do I solve this problem?
\n" ); document.write( "x^3+3x^2-4x-12=0
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\n" ); document.write( "I graphed the cubic and found a root at x = -2
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\n" ); document.write( "Use synthetic division to find the other zeroes:
\n" ); document.write( "-2)....1....3....-4....-12
\n" ); document.write( ".......1....1....-6...|..0\r
\n" ); document.write( "\n" ); document.write( "Quotient: x^2 + x -6
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\n" ); document.write( "Solve x^2 + x -6 = 0
\n" ); document.write( "Factor:(x+3)(x-2) = 0\r
\n" ); document.write( "\n" ); document.write( "Zeroes: x = -2, x = 2, x = -3
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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