document.write( "Question 711201: The length of a rectangle is 3 inches less than twice the width. The perimeter of the
\n" ); document.write( " rectangle is 90 inches. Find the dimensions of the rectangle.
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Algebra.Com's Answer #437328 by tutor_paul(519) $\"\"$ $\"About$

You can put this solution on YOUR website!
You can write 2 equations from the given information.
\n" ); document.write( "Define the following variables:
\n" ); document.write( "L=length
\n" ); document.write( "W=width
\n" ); document.write( "P=perimeter
\n" ); document.write( " $\"L=2W-3\"$
\n" ); document.write( " $\"P=2L%2B2W=90\"$
\n" ); document.write( "---------------
\n" ); document.write( "Solve 2nd Equation for L in terms of W:
\n" ); document.write( " $\"2L%2B2W=90\"$
\n" ); document.write( " $\"2L=90-2W\"$
\n" ); document.write( " $\"L=%2890-2W%29%2F2\"$
\n" ); document.write( " $\"L=45-W\"$
\n" ); document.write( "Substitute this expression for L into the first equation, and solve for W:
\n" ); document.write( " $\"45-W=2W-3\"$
\n" ); document.write( " $\"2W%2BW=45%2B3\"$
\n" ); document.write( " $\"3W=48\"$
\n" ); document.write( " $\"highlight%28W=16%29\"$
\n" ); document.write( "----------------
\n" ); document.write( "Substitute this value for W into the second equation and solve for L:
\n" ); document.write( " $\"2L%2B2%2816%29=90\"$
\n" ); document.write( " $\"2L%2B32=90\"$
\n" ); document.write( " $\"2L=58\"$
\n" ); document.write( " $\"highlight%28L=29%29\"$
\n" ); document.write( "=================
\n" ); document.write( "Good Luck,
\n" ); document.write( "tutor_paul@yahoo.com\r
\n" ); document.write( "
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