document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=62898>Question 62898</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Write the slope-intercept form of the equation of the line through (-1,2) that is perpendicular to the line x+3y=4  hope you can help, thanks </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #43730 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=43730\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> FIND THE SLOPE OF THE EQUATION X+3Y=4 THUS<BR>\n" );
document.write( "3Y=-X+4<BR>\n" );
document.write( "Y=(-1/3)X+4/3 THUS THE SLOPE IS -1/3<BR>\n" );
document.write( "A LINE PERPENDICULAR TO THIS LINE MUST HAVE A SLOPE THAT IS THE NEGATIVE RECIPRICLE OF THIS SLOPE THUS THE NEW SLOPE IS 3<BR>\n" );
document.write( "SO Y=3X+b NOW SUBSTITUTING THE X & Y VALUS FOR THE POINT WE GET THE Y INTERCEPT<BR>\n" );
document.write( "2=3*-1+b<BR>\n" );
document.write( "2=-3+b<BR>\n" );
document.write( "2+3=b<BR>\n" );
document.write( "5=b THUS WE HAVE THE FORMULAR FOR THIS LINE <BR>\n" );
document.write( "Y=3X+5 THAT HAS A SLOPE OF 3, A Y INTERCEPT OF 5 & PASSES THROUGH THE POINTS <BR>\n" );
document.write( "(-1,2)  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );